An elettric circuit

There exists an electric circuit that has an interruption. The -proper- length of the interruption is $L_0$. A tract of electric wire runs along the circuit with speed $v$. The -proper- length of the wire is $L_0$ too. In circuit reference system wire length is $L<L_0$, so the circuit is never closed. In wire reference system interruption length is $L<L_0$, so at some instant the circuit is closed. How can you explain the apparent contradiction?
Update(22/04/2008): Solution posted! (show solution)
In wire reference system, the circuit is just formally closed. Indeed the time in which it remains closed is not sufficient to permit the electric current flows. In this reference system, wire length is $ L_0 / \gamma $, where $\gamma$ is $ {(1-v^2/c^2)}^{-\frac{1}{2} $. So the time during which circuit is closed is $ \Delta t = L_0 \frac{1-1/ \gamma}{v} $ and in that time a signal that has the light speed run distance $ d = \frac{c(\gamma -1)}{v \gamma} L_0 < L_0 $. In conclusion if an electrical instrument is connected to circuit, then in both reference systems it is going to do not work.